COUNT_DISTINCT (Lakehouse v1)

Aggregate function.

The count(distinct …) function calculates the unique value of a set of values.

To obtain an estimated result from large data sets with little memory and time, consider using APPROX_COUNT_DISTINCT.

Analyze Syntax

func.count_distinct(<column>)

Analyze Examples

func.count_distinct(table.category).alias('unique_categories')

| unique_categories |
|-------------------|
|         2         |

SQL Syntax

COUNT(distinct <expr> ...)
UNIQ(<expr>)

Arguments

Arguments	Description
`<expr>`	Any expression, size of the arguments is [1, 32]

Return Type

UInt64

SQL Examples

Create a Table and Insert Sample Data

CREATE TABLE products (
  id INT,
  name VARCHAR,
  category VARCHAR,
  price FLOAT
);

INSERT INTO products (id, name, category, price)
VALUES (1, 'Laptop', 'Electronics', 1000),
       (2, 'Smartphone', 'Electronics', 800),
       (3, 'Tablet', 'Electronics', 600),
       (4, 'Chair', 'Furniture', 150),
       (5, 'Table', 'Furniture', 300);

Query Demo: Count Distinct Categories

SELECT COUNT(DISTINCT category) AS unique_categories
FROM products;

Result

| unique_categories |
|-------------------|
|         2         |